3x^2-38x-105=0

Solution for 3x^2-38x-105=0 equation:

3x^2-38x-105=0

a = 3; b = -38; c = -105;
Δ = b2-4ac
Δ = -382-4·3·(-105)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-52}{2*3}=\frac{-14}{6}
=-2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+52}{2*3}=\frac{90}{6}
=15
$